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crimeas [40]
3 years ago
13

Mary spent $15. If this was 20% of her earrings, how much money did she earned?

Mathematics
1 answer:
Fed [463]3 years ago
4 0

Hi, I'm happy to help!

First off, we need to arrange an equation for what is being asked. 15 is 20% of her earnings and we don't know her total earnings.

15=20%×__

We can write this percentage as

15=0.2×__

We then change the equation to do the inverse operation, which is division, this makes it easier to solve.

15÷0.2=__

Now, we solve

15÷0.2=75

<u>She earned $75</u>

<u></u>

I hope this was helpful, keep learning! :D

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3 years ago
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Ghella [55]

Answer:

Both angles have a measure of 134degrees, y = 27degrees.

Step-by-step explanation:

As per what is given in the problem:

There are 2 parallel lines, both are intersected by a transversal.

Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.

The is meanse that:

3y + 53 = 7y - 55

Solve using inverse operations:

3y + 53 = 7y - 55

     +55         +55

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/4      /4

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Now, substitute back in to find the value of the angle:

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7 0
3 years ago
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Step-by-step explanation:

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3 years ago
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\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

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\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

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\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

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<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

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