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Likurg_2 [28]
3 years ago
5

Solve: 9-(3-6)^2 / 4(5+2)-9

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0
9 - (-3)^2 / 4(7) -9

9 - (9)/ 28 - 9

0/21

0/21 = 0 

hope this helps
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Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi
Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


Therefore:

\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m


So:

\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)


Finally, the magnitude is:


\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

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Find the value of x in the figure below. Show your work.
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Answer:

Step-by-step explanation:

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Here are 4 fractions labelled A,B,C,D. A is 3/4 B is 5/6 C=16/25 D=9/15 Using the label A,B,C,D, Write the fractions in order of
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Answer:

Starting with the smallest, we will have; D , C, A, B

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Given;

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