Question

Answer the questions in the picture.

Answer 1

Step-by-step explanation:

Given:-

• The Values ( Attach by the User )

To find:-

• Mean
• Median
• Mode
• Range

Solution:- (Q.1)

$\sf \: Arithmetic \: mean = \dfrac{Sum \: of \: all \: observation}{No.of \: observations}\\\\\\: \implies \sf \: mean \: = \dfrac{1 + 1 + 1 + 1 + 3 + 3 + 4 + 4 + 4 + 8 + 12}{11}\\\\\\ : \implies \sf \: mean = \dfrac{42}{11} \\\\\\ : \implies \sf \: mean = 3.81$

Solution:- (Q.2)

$: \implies \sf \:median = \bigg({\dfrac{n + 1}{2} \bigg)^{th}}\\\\\\ :\implies \sf \:median = \bigg( {\dfrac{11 + 1}{2} \bigg)^{th}}\\\\\\: \implies \sf \:median = \bigg( \dfrac{12}{2} \bigg) ^{th}\\\\\\ : \implies \sf \:median = 6th \: item\\\\\\ : \implies \sf \:median = 3$

Solution:- (Q.3)

Mode = Number of Maximum times occurring in Observation.

Mode = 1 Because its Occurring most in the Observation.

Solution:- (Q.4):-

Range = Highest - Lowest

⠀⠀⠀⠀= ⠀⠀12 ⠀⠀- ⠀1

⠀⠀⠀⠀= ⠀⠀⠀⠀⠀11

.°. 11 is the Required Range

Answer 2

Answer:

MEDIAN = 6

Step-by-step explanation:

FORMULA = (n+1)÷2