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grandymaker [24]
3 years ago
11

A farmer owns a 2000-acre farm and can plant any combination of two crops, A and B. Crop A requires 1 person-day of labor and $9

0.00 of capital for each acre planted, while crop B requires 2 person-days and $60.00 of capital for each acre planted. Crop A produces $170.00 in revenue per acre, and crop B produces $190.00 in revenue per acre. The farmer has $150,000.00 of capital and 3000 person-days of labor available for the year. How many acres of each crop should the farmer plant in order to maximize the total revenue?
Mathematics
1 answer:
blagie [28]3 years ago
6 0
A+2b=3000
90a+60b=150000

-90a-180b=-127000
90a+60b=150000

-120b=-120000
b=1000

a+2000=3000
a=1000

crop a=1000
crop b=1000
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The table is show clearly in the figure attached.

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2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

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Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

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Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

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\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

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Rationalize

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In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

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