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dmitriy555 [2]
3 years ago
10

Simplify to create an equivalent expression of 2(−n−3)−7(5+2n)

Mathematics
1 answer:
musickatia [10]3 years ago
6 0
<h3>Answer:   -16n-41</h3>

Work Shown:

2(-n-3) -7(5+2n)

2(-n)+2(-3) - 7(5)-7(2n) ... distribute

-2n - 6 - 35 - 14n

(-2n-14n) + (-6-35)

-16n - 41

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Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?
zhuklara [117]

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

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4 0
3 years ago
Moby sold half his toy car collection, and then bought 12 more cars the next day. He now has 48 toy cars. How many cars did he h
castortr0y [4]

Answer: 72 cars.

Step-by-step explanation:

Let be "x" the number of toys that Moby had to start with.

According to the information given in the exercise, Moby sold half his toy car collection. This can be represented with the following expression:

\frac{1}{2}x

Then he bought 12 more cars, giving a total amount of 48 toy cars.

Therefore, the equation that represents this situation is the equation shown below:

x-\frac{1}{2}x+12=48

Now you must solve for "x" in order to find its value.

You get that this is:

\frac{1}{2}x+12=48\\\\\frac{1}{2}x=48-12\\\\\frac{1}{2}x=36\\\\x=(36)(2)\\\\x=72

7 0
4 years ago
Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $10 ever
Alexxandr [17]

Answer:

Tina would save the same amount using either option after 20 months.

With either option, Tina would save $700.

Step-by-step explanation:

This problem can be modeled by a first order equation:

Where Tina's saved money after n months is:

S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.

The first option is to put $500 away initially and save $10 every month, so:

S_{1}(n) = 500 + 10n

The second option is to put $100 away initially and save $30 every month, so:

S_{2}(n) = 100 + 30n

After how many months would Tina save the same amount using either option?

It will happen at the month n in which S_{1}(n) = S_{2}(n), so:

S_{1}(n) = S_{2}(n)

500 + 10n = 100 + 30n

500 - 100 = 30 - 10n

400 = 20n

20n = 400

n = \frac{400}{20}

n = 20.

Tina would save the same amount using either option after 20 months.

How much would she save with either option?

We can choose S_{1}(20) or S_{2}(20), since they are equal

S_{1}(20) = 500 + 10(20) = 500 + 200 = 700

With either option, Tina would save $700.

3 0
3 years ago
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