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storchak [24]
3 years ago
5

Write in standard form Thirty Two Thousand, four hundred ninety one

Mathematics
1 answer:
vekshin13 years ago
7 0

Answer:

32,491

Step-by-step explanation:

Thirty Two Thousand, four hundred ninety one = 32,491

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The population of a town can be modeled by P= 22,000 + 125t, where P represents the population and the t represents the number o
nlexa [21]
Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032
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A circular garden has a circumference of 113 yards. Lars is digging a straight line along a diameter of the garden at a rate of
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Answer:3hrs 59min

Step-by-step explanation:

πd=perimeter

(113÷3.14)

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Rewrite this percent as a decimal:<br> 80%
ella [17]

Answer:

.80

or

0.80

Step-by-step explanation:

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3 years ago
Giving brainliest !!!!
Artemon [7]
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Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]
Anastaziya [24]

Answer:

f_{avg}=e-1

Step-by-step explanation:

We are given that a function

f(x)=e^{\frac{x}{7}}

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx

f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}

By using the formula

\int e^{ax}=\frac{e^{ax}}{a}

f_{avg}=(e-e^0)=e-1

Because e^0=1

f_{avg}=e-1

Hence, the average value of function on interval [0,7]

f_{avg}=e-1

8 0
3 years ago
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