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qwelly [4]
3 years ago
12

A car drives for 1 hour 55 minutes with a constant speed of 36 km/h and then for another 1 hour 50 minutes with a constant speed

of 72 km/h. What distance did it go?
Mathematics
1 answer:
stich3 [128]3 years ago
7 0
----------------------------------------
Convert hours to minutes
----------------------------------------
1 hour 55 mins = 60 + 55 = 115 mins
1 hour 50 mins = 60 + 50 = 110 mins

_____________________________________________________

----------------------------------------
Speed = 36/h
----------------------------------------
1 hour = 36 km

----------------------------------------
Rewrite 1 hour as 60 mins
----------------------------------------
60 mins = 36 km

----------------------------------------
Find 1 min
----------------------------------------
1 min = 36 ÷ 60
1 min = 0.6 km

----------------------------------------
Find 115 mins
----------------------------------------
1 min = 0.6 km
115 min = 0.6 x 115 
115 min = 69km

_____________________________________________________

----------------------------------------
Speed = 72km/h
----------------------------------------
1 hour = 72 km

----------------------------------------
Write 1 hour as 60 mins
----------------------------------------
60 mins = 72 km

----------------------------------------
Find 1 min
----------------------------------------
1 min = 72 ÷ 60 
1 min = 1.2 km

----------------------------------------
Find 110 min
----------------------------------------
1 min = 1.2 km
110 min = 1.2 x 110 
110 min = 132 km

_____________________________________________________

----------------------------------------
Total Distance traveled:
----------------------------------------
69km + 132km = 201km

----------------------------------------
Answer: 201 km
----------------------------------------

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An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

<h3>What are inequalities?</h3>

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The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,

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