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Marat540 [252]
3 years ago
13

May someone explain this?Thanks❤

Mathematics
2 answers:
Arisa [49]3 years ago
8 0
To subtract fractions, find the least common denominator and then combine. The fraction would be 7/5. Then, convert it to a mixed number. Your answer would be 1 2/5
Georgia [21]3 years ago
4 0
2=10/10 so 10/10-3/5=10/10-6/10=4/10 or 2/5
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Find the Area of the composite shape shown below:
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Answer:

104 ft

Step-by-step explanation:

6 x 4 = 24

16 x 8 = 128

128 - 24 = 104 ft

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al lanzar 2 dados las sumas de sus caras superiores es 7. Hallar la probabilidad de que unas de las caras haya sido 3
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15/216 (6.944%)

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3 years ago
What are the domain and range of the function f(x)=3 to the power of x +5
emmasim [6.3K]

Answer:

Domain: (-∞,∞)

Range: (5,∞)

Step-by-step explanation:


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3 years ago
Angel Sanchez has 10 books on a shelf; 5 mysteries, 4 science fiction books, and 1 biography. Determine the probability of each
Cerrena [4.2K]

Answer:

a)  1/10 x 5/10 = 1/20

b) 1/10 x 5/9 = 1/18

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va
Lemur [1.5K]

Answer:

The mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

The probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

The probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

Step-by-step explanation:

Let <em>X</em> = total taxable earnings of workers.

The expected value of the random variable <em>X</em> is:

E (X) = <em>μ</em> = $28.29

The standard deviation of the random variable <em>X</em> is:

SD (X) = <em>σ</em> = $33.493.

The data was collected from 56 American counties.

The sample mean of a random variable is the an unbiased estimator of the population mean.

If repeated samples are collected from a population and the mean for each sample is computed then the expected value of the sample means is same as the population mean.

So the mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

According to the Central limit theorem if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n ≥ 30) from the population with replacement, then the distribution of the sample-means will be approximately normally distributed.

Then, the mean of the sample means is given by,  \mu_{\bar x}=\mu.

And the standard deviation of sample means is, \sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Compute the value of P (\bar X < 33) as follows:

P(\bar X

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

Compute the value of P (\bar X > 30) as follows:

P(\bar X>30)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{30-28.29}{33.943/\sqrt{56}})\\=P(Z>0.38)\\=1-P(Z

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

5 0
3 years ago
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