3 years ago

What is the point slope form of the line with slope -3/7 that passes through the point (5,8)?

Mathematics

1 answer:

prohojiy [21]3 years ago

5 0

Answer:

y-8=-3/7(x-5)

Step-by-step explanation:

the equation goes like : y-y1=m(x-x1) now just input all of that stuff where it goes and you get your answer. m is slope btw

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Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

Factored form of a parabola

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

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2 years ago

HURRY MARK BRAINLIEST A system of equations is graphed on a coordinate plane.

Scilla [17]

Answer:

-1,0

Step-by-step explanation:

its an estamant so its nothing exactly

its closest to -1 and closest to 0

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ddd [48]

The answer is C 80
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5a4
=80

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If point Q does not lie on the x-axis or the y-

natta225 [31]

Answer:

E. II or IV only

hope it helps :)

mark brainliest!!

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snow_lady [41]

ok ok ok bro i understand i love you

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