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lys-0071 [83]
2 years ago
5

Graph the solution for the following system of inequalities. Click on the graph until the correct solution is displayed. x + y &

gt; 3 x + y < -4

Mathematics
2 answers:
Y_Kistochka [10]2 years ago
5 0

Answer:

This is an equation. Solutions: x=1.

N76 [4]2 years ago
3 0

Answer:

The graph for the following system of inequalities is attached below.

Step-by-step explanation:

The given system of inequalities is

x+y>3                    .... (1)

x+y                  .... (2)

From inequality (1) and (2) it is clear that (x+y) is greater than 3 adn 3 is not less than -4. So, the given system of inequality has no feasible reason or solution.

The related equation of first inequality is

x+y=3

Put x=0 to find the y-intercept.

0+y=3\Rightarrow y=3

The y-intercept is 3.

Put y=0 to find the x-intercept.

x+0=3\Rightarrow x=3

The x-intercept is 3.

The related equation of second inequality is

x+y=-4

Put x=0 to find the y-intercept.

0+y=-4\Rightarrow y=-4

The y-intercept is -4.

Put y=0 to find the x-intercept.

x+0=-4\Rightarrow x=-4

The x-intercept is -4.

The related lines are dotted line because the sign of inequalities are > and <.

Check each inequality be (0,0).

0+0>3

0>3

This statement is false. So the shaded region of first inequality is opposite sides of the origin.

0+0  

0  

This statement is false. So the shaded region of first inequality is opposite sides of the origin.

The graph for the following system of inequalities is attached below.

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Answer:

\text{D. }b^2-4ac>0

Step-by-step explanation:

The equation b^2-4ac represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.

For any quadratic:

  • If the discriminant is positive, or greater than 0, the quadratic has two solutions
  • If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).
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In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have b^2-4ac>0.

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2 years ago
Round 10.95 to the nearest tenth
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Hi there! To round 10.95 to the nearest tenth, we find the number in the tenth place, which is 9 and look one place to the right. Round up if the number is greater than 5 or equal to 5 and round down if its less than 5.

The answer is 11.0 or just 11.

<em>Ed: Explanation below.</em>

<em />

11.00

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10.98

10.97

10.96

10.95 Look at the 9. Then look to the right. Do I round up or down?

10.94

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10.92

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If the number is greater or equal to 5, you round up. If the number is smaller than 5, you round down. 9 is greater than 5, so we round up.

Therefore, the answer is 11.

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