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trapecia [35]
3 years ago
9

Find the unit rate of 3÷12​

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

1/4

Step-by-step explanation:

3/12

Simplify. Both numbers can be divided by 3.

3/12 = 1/4

Lubov Fominskaja [6]3 years ago
8 0

Answer:

0.25

Step-by-step explanation:

3÷12=0.25

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12.89503 ronded to the hundreths is​
Tpy6a [65]

Answer:

12.90

Step-by-step explanation:

The hundredth is the second decimal place.

Basically we want to drop the numbers after the 9.

12.89  <u>5</u>03

Use the underlined decimal place, right after what you are rounding to, to determine if you round up or down.

For numbers 0-4, round down (keep the number). For numbers 5-9, round up (increase by 1).

We need to round up because 5 is in the range 5-9.

"Add" 1 to the hundredth decimal place and treat it like addition:

.   12.89

<u>+    0.01</u>

.    12.90

7 0
3 years ago
At your local farmers market , it costs $10 to rent to rent a stand , and $7 for every hour you stay there . If you paid a total
Arisa [49]

Subtract the rental fee, then divide the left over amount by the cost per hour.

38-10 = 28

28 / 7 = 4

The answer is 4 hours.

8 0
3 years ago
What is the equivalent exxpression of 8b+8-4b-3
sergiy2304 [10]
8b + 8 - 4b - 3

Combine like terms:-

(8-4)b + 8 - 3
4b + 8 - 3 
4b + 5 
4 0
3 years ago
Please answer this probability question.
svet-max [94.6K]

Answer:

C

Step-by-step explanation:

its 2/5 for the evens 3/5 for odds multiply and you get 6/25

7 0
3 years ago
A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
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