Find the unit rate of 3÷12

12.89503 ronded to the hundreths is

Tpy6a [65]

Answer:

12.90

Step-by-step explanation:

The hundredth is the second decimal place.

Basically we want to drop the numbers after the 9.

12.89 <u>5</u>03

Use the underlined decimal place, right after what you are rounding to, to determine if you round up or down.

For numbers 0-4, round down (keep the number). For numbers 5-9, round up (increase by 1).

We need to round up because 5 is in the range 5-9.

"Add" 1 to the hundredth decimal place and treat it like addition:

. 12.89

. 12.90

7 0

3 years ago

At your local farmers market , it costs $10 to rent to rent a stand , and $7 for every hour you stay there . If you paid a total

Arisa [49]

Subtract the rental fee, then divide the left over amount by the cost per hour.

38-10 = 28

28 / 7 = 4

The answer is 4 hours.

8 0

3 years ago

What is the equivalent exxpression of 8b+8-4b-3

sergiy2304 [10]

8b + 8 - 4b - 3

Combine like terms:-

(8-4)b + 8 - 3
4b + 8 - 3
4b + 5

4 0

3 years ago

Please answer this probability question.

svet-max [94.6K]

Answer:

C

Step-by-step explanation:

its 2/5 for the evens 3/5 for odds multiply and you get 6/25

7 0

3 years ago

A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than

vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

$H_0: p \leq 0.05$

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

$H_a: p > 0.05$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that $\mu = 0.05, \sigma = \sqrt{0.05*0.95}$

A random sample of 300 items taken from the production line contained 27 defective items.

This means that $n = 300, X = \frac{27}{300} = 0.09$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}$

$z = 3.18$

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0

3 years ago

Find the unit rate of 3÷12​

Find the unit rate of 3÷12