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Alchen [17]
3 years ago
15

Compare the arrangements of individual particles in solids, liquids, and gases?

Chemistry
1 answer:
salantis [7]3 years ago
4 0
Solid particles are all compacted together, liquid particles are not as close as solid particles but still move together, and gas particles do not stay together

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To what category of elements does an element belong if it is a poor conductor of electricity
Yuri [45]

I was wondering the same thing my dude

3 0
3 years ago
Se sabe que 10 g de calcio reaccionan con 4 g de oxígeno para obtener 14 g de óxido de calcio. Indica la cantidad de óxido de ca
egoroff_w [7]

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

2Ca+O_2\rightarrow 2CaO

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

4 0
3 years ago
Read 2 more answers
What is the molarity of a solution made by mixing 2.80 g of koh with enough water make 750 ml of solution?
Travka [436]
<span>Molarity is expressed as the number of moles of solute per volume of the solution. We calculate as follows:

2.80 g ( 1 mol / 56.11 g ) = 0.05 mol KOH

Molarity = 0.05 mol KOH / 750 mL ( 1 L / 1000 mL )
Molarity = 0.07 M

Hope this answers the question. Have a nice day.</span>
7 0
3 years ago
Jwjajajahwhab a a skwiwiwiahah​
FrozenT [24]
Thank you :))) for the points have a great day
8 0
3 years ago
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A pure substance is matter that consists of matter with a composition that
sashaice [31]
Is constant (matter that has a composition that is the same everywhere)
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3 years ago
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