All categories

2 years ago

The Marketing Department is deciding which classes to offer over the summer. The classes under consideration are:

Mathematics

1 answer:

svetlana [45]2 years ago

7 0

Answer:

Step-by-step explanation:6x8=48

You might be interested in

What is the word for "numbers with square roots that are whole numbers"? I have no idea!

topjm [15]

Perfect squares i think

8 0

2 years ago

Read 2 more answers

What factors of 32 add up to -12

irakobra [83]

Answer: -8 and -4

This is something you do through trial and error. Making a list or a table like shown below might help.

8 0

2 years ago

((PLEASE HELP ASAP!! D:)) Natasha bought a tennis racket that was marked down in price, p, by 20%. Write an expression with TWO

kumpel [21]

Answer: p - 0.2p

Step-by-step explanation:

Given the following :

Original Price of tennis racket = p

Mark down or discount on original price = 20% of original price = (20/100) × p = 0.2p

Amount after discount = Amount paid by Natasha

Amount after discount = Original price - Discount

Amount after discount = p - 0.2p

Amount paid by Natasha = p - 0.2p

7 0

2 years ago

Does anyone know what the formula for the area of a circle is?

Sloan [31]

Answer:

search up-area of circle formula and circumference of a circle formula

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |subtract $y$ from both sides

$\dfrac{2}{3}x-y+b=0$ |multiply both sides by 3

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |multiply both sides by $\sqrt{13}$

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |divide both sides by 3

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago