What values of x makes this equation true? (2x+6)^2-14=30

1 answer:

6 0

$(2x+6)^2-14=30 \\ \\ (2(x + 3))^2 - 14 = 30 \\ \\ 2^2 (x + 3)^2 - 14 = 30 \\ \\ 4(x + 3)^2 - 14 = 30 \\ \\ 4(x + 3)^2 = 30 + 14 \\ \\ 4(x + 3)^2 = 44 \\ \\ (x + 3)^2 = \frac{44}{4} \\ \\ (x + 3)^2 = 11 \\ \\ x + 3 = \pm \sqrt{11} \\ \\ x = \sqrt{11} - 3, - \sqrt{11} - 3 \\ \\$

The final result is: x = √11 - 3, -√11 - 3.

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