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chubhunter [2.5K]
3 years ago
6

In 9 hours, Yoko reads 72 chapters of a book. What is her rate in chapters per hour?

Mathematics
2 answers:
Deffense [45]3 years ago
6 0

72/9 = 8

She read 8 chapters per hour.

mel-nik [20]3 years ago
5 0

Answer:

8

Step-by-step explanation:

You do 72 ÷ 9 which equals 8 which is your hourly rate

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Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one
soldier1979 [14.2K]

Answer:

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

AC is the diagonal whose length is 18.79 inches.

The length of wall AB is 17 inches.

From the given information, we have to determine the length of the BC, which is depicted a , because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.

Thus, inches

and hence, the given room is not a square.

Step-by-step explanation:

6 0
3 years ago
Find the surface area of a cylinder with a base radius of 2 in and a height of 5 in
Vsevolod [243]

Answer:

r = 2 \\ h = 5 \\ a = 2\pi \: rh + 2\pi {r}^{2}  \\  = 2\pi \times 2 \times 5 + 2\pi {2}^{2}  \\  = 20\pi + 8\pi \\  = 28\pi \\  = 28 \times 3.14 \\  = 87.92 {unit}^{2}  \\ thank \: you

7 0
3 years ago
How can you express 5 1/3 + (-7 2/3) as the sum of its integer and fractional parts
Yuliya22 [10]

Answer:

-7/3

Step-by-step explanation:

-7 2/3=-23/3

5 1/3=16/3

-----------------

16/3+(-23/3)

16/3-23/3

-7/3

6 0
3 years ago
Which is an example of the associative property?
Mrac [35]
I believe that the answer is C.
5 0
3 years ago
Read 2 more answers
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
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