Answer:
Step-by-step explanation: yes because when rewritten in standard form the x term will still be raised to the 2nd power.
Answer:

Step-by-step explanation:
<h2>

</h2><h2>

</h2><h2>

</h2><h2>

</h2><h2>

</h2><h2>

</h2>

- hope it helps! -
<h2 />
Slope = rise/run = (change in y)/(change in x)
Slope = (4-6)/(0-(-4)) = (-2)/(4)
Slope = -1/2 = -0.5
You need to divide the miles by the hours to et the Average speed.
M divided by h = s
Because to get the mph (miles per hour) you multiply the average speed to the hours.
S•h=mph
Answer: 
Step-by-step explanation:
Given
Cost per student in the year 1978 is $2200
The cost increases to $10,300 in 2008
Suppose
is the linear equation defining the cost per student after x years
Substitute the value for 1978

After 30 years it becomes

Thus, the linear equation becomes
