5 + 5 is 10...
Start with 5 on one hand and use the other hand (count 5 on that one)
Word problem to make this a little bit 'simplier'
You have 5 squares (◾◾◾◾◾) and you tag along have more (◾◾◾◾◾). How many do you have all together? 10 squares.
◾◾◾◾◾ + ◾◾◾◾◾ (⬅count those squares )
You can choose from 20 students for the first student, 19 for the second, 18 for the third, ..., 14 for the seventh student.
That gives you 20 * 19 * 18 * 17 * 16 * 15 * 14.
That number would allow you to write the students in different order. Since order here does not matter, any group with the same students in any order is the same group, you need to divide by the number of way you can order 7 items. Divide by 7 * 6 * 5 * 4 * 3 * 2 * 1
(20 * 19 * 18 * 17 * 16 * 15 * 14)/(7 * 6 * 5 * 4 * 3 * 2 * 1) = 77,520
Answer: 77,520
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
Answer:
Step-by-step explanation:
Answer:
Addition prop of equality, multiplication prop of equality, multiplication prop. of equality
Step-by-step explanation:
For the first one, we know that in order to solve the equation, we need to add 3 to both sides of the equation. When you add a value to both sides of the equation, you're using the addition property of equality.
For the second one, we know that in order to solve the equation, we need to multiply both side by 1/6 (to cancel the 6 out on the left side). When you multiply something to both sides of the equation, you're using the multiplication property of equality.
For the third one, we know that in order to solve the equation, we must multiply both sides of the equation by 5. Like the second problem, this would be the multiplication property of equality (since you're multiplying both sides of the equation by the same thing).
