Round 149,640 to the nearest thousand.

BRAINLIEST BRAINLIEST BRAINLIEST PLEASE ANDSER IT IS TIMED THANK YOU SO MUCCH

Doss [256]

Answer:

x=-b/2a

Step-by-step explanation:

hope that helps :)

mark as brainliest please :)

8 0

3 years ago

Miguel tells his teacher1/5 is the same as 20%. Which best justifies Miguel’s answer? a.5 goes into 100 twenty times, so 20% is

svetoff [14.1K]

Answer:

C. 5 goes into 100 twenty times, and 1 times 20 is 20

Step-by-step explanation:

Since, we know that when we multiply both numerator and denominator of a fraction by a same number then we obtain an equivalent fraction,

Here, the given fraction,

$\frac{1}{5}$

By the above statement,

$\frac{1}{5}=\frac{1\times 20}{5\times 20}=\frac{20}{100}$

Now,

$a\%=\frac{a}{100}$

$\implies \frac{20}{100}=20\%$

Hence,

$\frac{1}{5}=20\%$

Option C is correct.

3 0

3 years ago

Read 2 more answers

Solve the problem below by finding a common denominator 1/3 - 1/5

sweet [91]

Answer:

2/15

Step-by-step explanation:

1/3-1/5

5/15-3/15

= 2/15

3 0

2 years ago

Read 2 more answers

What is the combined weight of all the kittens? Weight of kittens: 1/4 pound: 3 kittens. 3/8 pound: 2 kittens. 1/2 pound: 4 kitt

Naya [18.7K]

Answer:

6 pounds

Step-by-step explanation:

1/4 times 3 = 3/4

3/8 times 2: 6/8 = 3/4

1/2 times 4: 4/2 = 2

5/8 times 4: 20/8 = 2 1/2

3/4 + 3/4 = 6/4 = 1 1/2

2 + 2 1/2 + 1 1/2 = 6 pounds

5 0

3 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago