3.345 meter s is bigger than 3.35?

Mathematics

2 answers:

garri49 [273]3 years ago

7 0

No, 3.345m is not greater than 3.35, because it is 3.35 is the same thing as 3.350.

masha68 [24]3 years ago

6 0

Hi , 3.35 is bigger than 3.345 .

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each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the per

Montano1993 [528]

<h3>Answer:-</h3>

192 cm²

<h3>Step by step explanation :-</h3>

Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .

According to Pythagoras Theorem :-

=> base² + perpendicular ² = hypontenuse ²

=> 12² + x² = (x+4)²

=> 144 + x² = x² + 16 + 8x

=> 8x = 144-16

=> 8x = 128

=> x = 128/8

=> x = 16 cm .

Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.

= 1/2 * 16 cm * 24cm .

= 192 cm²

<h3>★ Hence the area of the triangle is 192 cm² .</h3>

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3 years ago

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Marrrta [24]

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4 0

3 years ago

Limit of x^2-81/x+9 As x goes toward -9

Semmy [17]

Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
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The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18

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3 years ago

Which fraction is equivalent to 3/5

pentagon [3]

Answer:

12/20

Step-by-step explanation:

5 0

3 years ago

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The expression 3(x-9) is equivalent to (Look at picture for answer choices)

Vaselesa [24]