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3 years ago

Hey guys I need help simplifying this radical expression please. ASAP please.

Mathematics

1 answer:

fiasKO [112]3 years ago

6 0

Answer:

go on symbolab type the equation in and it gives u anwsers and work

Step-by-step explanation:

=\frac{4}{\left(x+2\right)\left(x+4\right)}

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What are axioms in algebra called in geometry?

Hatshy [7]

In geometry, axioms are actually called Postulates and their creation is called postulation.

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3 years ago

Can someone solve this? and tell me how?

maksim [4K]

Answer:

1/3

Step-by-step explanation:

When working with balanced expressions (stuff on both sides of the equal sign), "what you do to one side, you do to the other", which keeps it balanced.

The first thing we notice is the exponent 1/4, which is one both sides, so we can get rid of it on both sides by using the <u>reverse operation</u>.

The reverse of exponents is <u>square root</u>.

$(4x + 10)^{\frac{1}{4}} = (9 + 7x)^{\frac{1}{4}}\\\sqrt[\frac{1}{4}]{(4x + 10)^{\frac{1}{4}}} = \sqrt[\frac{1}{4}]{(9 + 7x)^{\frac{1}{4}}}\\\\4x + 10 = 9 + 7x$

Isolate x to solve. Separate the variables and non-variables.

4x + 10 = 9 + 7x

4x - 4x + 10 = 9 + 7x - 4x Subtract 4x from both sides

10 = 9 + 3x

10 - 9 = 9 - 9 + 3x Subtract 9 from both sides

1 = 3x Divide both sides by 3 to isolate x

x = 1/3 Answer

8 0

3 years ago

The bar graph below displays students’ responses to the question "What caffeinated drinks do you consume?”

alekssr [168]

Answer:

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Step-by-step explanation:

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3 years ago

Catherine walks her dog 3/4 mile everyday how far does she walk each week

fenix001 [56]

Catherine walks her dog 5.25 miles because there are 7 days in one week and 3/4 x 7 = 5.25

5 0

3 years ago

Read 2 more answers

Please help me with this

Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

$\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}$

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

$\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }$

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

$\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }$

Thefore the required answer is ,

$\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}$

4 0

3 years ago

Read 2 more answers