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lana [24]
3 years ago
15

Help me please if you can

Mathematics
1 answer:
jolli1 [7]3 years ago
3 0
It is either top left or bottom right, I cannot see the numbers clearly.
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40x-25 y = 180<br> Solve for x and y
Lostsunrise [7]

Answer:

x=

5 /8y+9/2

Step-by-step explanation:

6 0
3 years ago
Winston's team participated in a total of 22 chess matches. Winston
Zepler [3.9K]

Answer:

Peter Jonathan Winston (March 18, 1958 – disappeared January 26, 1978) was an American chess player from New York City

Step-by-step explanation:

In late 1977, Winston attended a FIDE-rated tournament at Hunter College High School in New York City. Despite being one of the highest-rated players in the tournament, Winston lost all nine of his games. A few months later, on January 26, 1978, following further surprising game losses, Peter Winston vanished and was never heard from again. According to some sources, Winston's disappearance occurred when he left his home without money, identification, or luggage during a severe winter storm. Many chess players who were close to or acquainted with Winston claim that the champion chess player's mental health had deteriorated, along with his game performance, in the last few years of his life, and that the decline in his mental health may have led to his disappearance.

3 0
2 years ago
Read 2 more answers
Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}

3 0
3 years ago
A farmer has a feed trough in the shape of rectangular prism with a height of 40 cm and a base that is 30 cm wide by 200 cm long
inysia [295]

Answer:

Step-by-step explanation:

You're welcome :)

5 0
3 years ago
ΔABC is a right triangle. Prove: a2 + b2 = c2 Right triangle BCA with sides of length a, b, and c. Perpendicular CD forms right
777dan777 [17]

Answer: Pythagorean Theorem Pieces of Right Triangles is not a justification for the proof.

Explanation : Here, \triangle ABC is a right triangle with sides a, b and c. Perpendicular CD forms right triangles BDC and CDA.

CD measures h units, BD measures y units, DA measures x units.

Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b, segment AB = c,  segment CD = h,  segment DB = y, segment AD = x,

y + x = c

a/c=y/a( Similarity theorem in triangles ABC and DBC )

a^2 = cy------(1) (Cross Product Property)

Similarly, b^2 = cx (Similarity theorem in triangles ABC and ADC)---------(2)

a^2 + b^2 = cy + cx(after adding equation (1) and (2) )

a^2 + b^2 = c(y + x)( By additional property of equality)

a^2 + b^2 = c^2. ( because y + x=c)

Thus, it has been proved that except Pythagorean Theorem Pieces of Right Triangles we use all other properties.

8 0
3 years ago
Read 2 more answers
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