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-BARSIC- [3]
3 years ago
9

How do you find the y-intercept and the slope for number 11

Mathematics
1 answer:
Pavel [41]3 years ago
7 0

slope = y2-y1 / x2-x1=

-1 -5 / 2 - -1 = -6/3 = -2

slope = -2

y intercept = y =mx +b

y = -2x +b

y=-2*-1 +b

5 = -2 +b

b = 5-2

b =3

y intercept = 3

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Are the following lines parallel? <br><br> y = -3x + 1 <br><br> y = 4 - 3x
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2 years ago
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
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We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
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=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
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Check orthogonality with normal vectors using scalar products
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