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Nana76 [90]
3 years ago
15

Generating Equivalent Expressions : simplify

Mathematics
1 answer:
laiz [17]3 years ago
5 0

Expand

z^3 + 5z + 15 + 8 - 4z^2

Collect like terms

z^3 + 5z + (15 + 8) - 4z^2

<u>Simplify </u>

<u>z^3 + 5z + 23 - 4z^2</u>

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The ratios in an equivalent ratio table are 3.12, 4.16, and
OleMash [197]

Answer:

maybe 6.24

sorry if wrong

Step-by-step explanation:

5 0
3 years ago
What is the solution of the given inequality?<br> -4(2x+1)&lt;_3(x-5)
soldi70 [24.7K]

Answer:

x ≥ 1

Step-by-step explanation:

Solve the inequality by solving for x.

Solve:

-4(2x + 1) ≤ 3(x - 5)

Use the distributive property.

-8x - 4 ≤ 3(x - 5)

-8x - 4 ≤ 3x - 15

Subtract 3x from both sides.

-11x - 4 ≤ -15

Add 4 to both sides.

-11x ≤ -11

Divide both sides by -11, also flip the inequality since you're dividing by a negative number.

x ≥ 1

Your final answer would be x ≥ 1

4 0
3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
If a angle turns one ninth what degrees is it
irina1246 [14]
It's 10 degrees I believe
7 0
3 years ago
(05.03)
iren [92.7K]

x=2

1:Subtract 2x from both sides.

2:Combine 2/3 x and -2x to get -4/3

3:Subtract 3/8 from both sides. Anything subtracted from zero gives its negation.

4:Multiply both sides by -3/4,the reciprocal of -4/3

5:Multiply − 3/8 ​ times − 4/ 3 ​ by multiplying numerator times numerator and denominator times denominator.

6:Do the multiplications in the fraction −8(−3) over 3x4.

x=24/12

Divide 24 by 12 to get 2.

x=2

​

8 0
2 years ago
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