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4 years ago

15

Generating Equivalent Expressions : simplify

1 answer:

laiz [17]4 years ago

5 0

Expand

z^3 + 5z + 15 + 8 - 4z^2

Collect like terms

z^3 + 5z + (15 + 8) - 4z^2

<u>Simplify </u>

<u>z^3 + 5z + 23 - 4z^2</u>

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Given the arithmetic sequence an= 2 - 3(n - 1), what is the domain for n?

wel

Generally we use n as a counter and begin it with 1: the first term is obtained when n = 1. Thus, n must be a positive integer, 1 or greater: {1, 2, 3, ... }.

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3 years ago

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Hi who can help me do this 2quetion,I will mark brainlest

hodyreva [135]

Step-by-step explanation:

$8. log_{10}(2.15) = 0.332 \: then \: log_{10}(21500) = ..... \\ log(21500) = log(2.15 \times 10000) \\ = log(2.15) + log(10000) \\ = log_{10}(2.15) + log_{10}( {10}^{4} ) \\ = 0.332 + 4 log_{10}(10) \\ = 0.332 + 4(1) \\ log_{10}(21500) = 4.332$

9. log(2)=a, log(3)=b, then log(36)=______

log(36) = log(6*6) = log(6) + log(6)

log(36)= log(6) + log(6)

log(36) = log(3*2) + log(3*2)

log(36) = (log(3) + log(2)) + (log(3) + log(2))

log(36) = (a + b) + (b + a)

log(36) = a + b + b + a

log(36) = 2a + 2b

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3 years ago

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3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

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3 years ago

9 hundreds =equals <br><br> tens

Lelechka [254]

90 tens hopefully this helped

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3 years ago

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