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oksian1 [2.3K]
3 years ago
12

HELPPP PLLLZZZ III BEEEG

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0
Asked and answered elsewhere.
brainly.com/question/9124477
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Is the orthocenter of a triangle on the inside ?
likoan [24]

Answer:

It turns out that all three altitudes always intersect at the same point - the so-called orthocenter of the triangle. The orthocenter is not always inside the triangle. If the triangle is obtuse, it will be outside. To make this happen the altitude lines have to be extended so they cross.

7 0
3 years ago
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Plzzz help....I am timed...There will be a picture provided....You will get 30 points!!! MATHH
xxMikexx [17]

Answer:

It should be the last one, She made a sign error when multiplying.

3 0
2 years ago
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Use this formula to find all the solutions of the equation. (Round terms to four decimal places)
Misha Larkins [42]
I might be misreading something here but if:

x^5+243=0  subtract 243 from both sides

x^5=-243  raise both sides to the 1/5 power  (or take the fifth root of both sides)

x=-3

So there is only one solution, x=-3
3 0
3 years ago
Question 1
gulaghasi [49]

Answer:

C

Step-by-step explanation:

A function is where each input has a single output.

(A) There can be a different amount of students in a class (e.g. 21 or 22) that have the same class length

(B) There can be multiple things that Mike can order with $1

(D) There can be multiple students have the same GPA

(C) There is one button for each snack item

8 0
2 years ago
What is the value of q?
andre [41]

Answer: here

Step-by-step explanation:riangles QST and RST are similar.  Therefore, the following is true:

q       s

--- = ----   This results in 10q=rs.

r      10

Also, since RST is a right triangle, 4^2 + s^2 = q^2.

Since QST is also a right triangle, s^2 + 10^2 = r^2.  

           4      s

Also:  ---- = -----    which leads to s^2 = 40

           s      10

Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2

Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)

hope it helps

6 0
3 years ago
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