Answer:
The answer is 3
Step-by-step explanation:
List all prime factors
15:1,3,5,
27:1,3,
Biggest one is 3
(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)
… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)
… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))
… = (2 - 2√3 <em>i</em> ) / 4
… = 1/2 - √3/2 <em>i</em>
… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))
… = exp(<em>i</em> arctan(-√3))
… = exp(-<em>i</em> arctan(√3))
… = exp(-<em>iπ</em>/3)
By DeMoivre's theorem,
[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1
X = 19.
Explanation:
This expression is vertical from the angle 135, meaning it is congruent. With that being said, we would need to find what 7 multiplies by to give us 2 less than 135, which would be 133. Because 133 divided by 7 equals 19, x = 19. If we plug this in, we get the following equation: 7(19) + 2 = 135.
1.) M is less than 4
2.) S≥30
Explanation:
S=Shawn. Shawn is older than 30 or equal to the age of 30. Shawn has to be at least 30 years old he can’t be 29 years old and lower. He has to be 30+
There is only 1 remaining side
We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:
c^2 = a^2 + b^2 -2ab *cos(C)
c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)
c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156
c^2 = 0.3611111111 + 0.029052
c^2 = 0.3901631111
c = 0.6246303796
