Ask question

Ask question

All categories

2 years ago

11

Which statements describe the function f(x) = 3(1/3)x? Check all that apply. Each successive output is the previous output divid

ed by 3. As the domain values increase, the range values decrease. The graph of the function is linear, decreasing from left to right. Each successive output is the previous output multiplied by 3. The range of the function is all real numbers greater than 0. The domain of the function is all real numbers greater than 0.

2 answers:

harkovskaia [24]2 years ago

7 0

Answer: A, B, E

Step-by-step explanation:

A:Each successive output is the previous output divided by 3.

B:As the domain values increase, the range values decrease.

E:The range of the function is all real numbers greater than 0.

I got it right on my test

Citrus2011 [14]2 years ago

6 0

Answer: A,b,e

A:Each successive output is the previous output divided by 3.

B:As the domain values increase, the range values decrease.

E:The range of the function is all real numbers greater than 0.

These are the answers on e2020. Hope this helps

You might be interested in

The graph of y=x^3 is transformed as shown in the graph below. Which equation represents the transformed function?

omeli [17]

Answer:

y = (-x)^3 - 4

Step-by-step explanation:

Ok, for the function:

y = x^3

When x = 0, we have:

y = 0^3 = 0

So the original graph passes through the point (0, 0)

If we look at the given graph, we can see that the y-intercept (the value of y when x = 0) is:

y = -4

So, this is the graph of y = x^3 moved down 4 units.

You can also see that the graph goes downward as x increases (and up as x decreases) while for the function:

y = x^3

as x increases, we should see that y also increases.

Then we have a reflection across the x-axis.

Ok, now let's describe a vertical shift.

For a general function f(x), a vertical shift of N units is written as:

g(x) = f(x) + N

if N is positive, the shift is upwards

if N is negative, the shift is downwards.

And for a function f(x), a reflection across the x-axis is written as:

g(x) = - f(x)

Here we first apply the reflection across the x-axis, so we get:

g(x) = -f(x)

now we apply the shift 4 units downwards

g(x) = - f(x) - 4

replacing f(x) by our function, x^3

we get:

g(x) = -x^3 - 4

And because of the odd power, we can write:

-x^3 = (-x)^3

Then the function is:

g(x) = (-x)^3 - 4

The correct option is the last one.

y = (-x)^3 - 4

3 0

3 years ago

3/7 is reduced to what lowest term?

sweet [91]

It can't be simplified, it is already in its lowest term

5 0

3 years ago

Read 2 more answers

Please help Explanation will be appreciated thanks,

Genrish500 [490]

Answer: A; 6.3%

Step-by-step explanation:

Problem 1

For the first problem, we first want to find y so that we can plug it into the expression.

We can use elimination method for the system of equations to solve.

3x+3y=21

3x-y=5

We subtract both equations to eliminate x.

4y=16 [divide both sides by 4]

y=4

Now that we know y, we can plug it into the expression.

$\frac{4}{2} -3$ [divide]

$2-3$ [subtract]

$-1$

We know that the answer is A.

--------------------------------------------------------------------------------------------------------

Problem 2

For the second problem, we need to know how to calculate percent error. The formula for precent error is $\frac{|measured-exact|}{exact} *100%$ . We know that the exact value is 80 because the buyer was supposed to given 80. 75 is the measured value because that was what the buyer was given.

$\frac{|75-80|}{80} *100%$ [subtract]

$\frac{|-5|}{80} *100%$ [solve absolue value]

$\frac{5}{80} *100%$ [divide]

$0.0625*100%$ [multiply]

$6.25$

Since the problem said to round to one decimal place, we know that the answer is 6.3%.

4 0

2 years ago

Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.

meriva

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}$

$\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}$

5 0

2 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

a)

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

b)

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

c)

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago