Step-by-step explanation:
K is an upper bound for│f"(x)│on the interval [0, 1], so x ≤ 1.
Sine and cosine have maximums of 1, so an upper bound of │f"(x)│is:
│f"(x)│≤ (76 · 1 + 152 · 1 · 1)
│f"(x)│≤ 228
Answer:
60, 75
150 165
240 255
330 345
Step-by-step explanation:
csc 4 theta = -2 sqrt(3)/3
Write in terms of sin
1/ sin (4 theta) = -2 sqrt(3)/3
Using cross products
-2 sqrt(3) = 3 sin (4 theta)
Divide each side by 3
-2 sqrt(3)/3 = sin (4 theta)
Take the inverse sin on each side
sin ^ -1(-2 sqrt(3)/3) = sin ^ -1 (sin (4 theta))
240 +360n = 4 theta
and 300 +360n = 4 theta where n is an integer
Dividing each side by 4
240/4 +360n/4 = 4/4 theta and 300/4 +360n/4 = 4/4 theta
60 + 90n = theta and 75 +90n = theta
We want all the values between 0 and 360
Let n=0
60, 75
n=1
60+90=150 and 75+90 =165
n=2
60+180= 240 75+180=255
n=3
60+270 = 330 75+ 270 =345
C.) -1.
Explanation: 4 + -5 = -1. When you have a negative number plus a positive you subtract. Then take the highest numbers positive or negative symbol. Hope that helps.
Answer:
7√2
Step-by-step explanation:
The correct answer is 6,8
