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4 years ago

How are gallons and fluid ounces related

2 answers:

7 0

These are the fluid ounce, cup, pint,quart, and gallon. These measurement units are related to one another, and capacity can be described using any of the units. Typically, people use gallons to describe larger quantities and fluid ounces, cups, pints, or quarts to describe smaller quantities.

mart [117]4 years ago

5 0

They both are a type of measurement

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How to find the equation of this line?

Bad White [126]

Answer:

y = - $\frac{6}{7}$ x - $\frac{10}{7}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 2 ) and (x₂, y₂ ) = (3, - 4) ← 2 points on the line

m = $\frac{-4-2}{3+4}$ = - $\frac{6}{7}$ , thus

y = - $\frac{6}{7}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 4, 2 ), then

2 = $\frac{24}{7}$ + c ⇒ c = 2 - $\frac{24}{7}$ = - $\frac{10}{7}$

y = - $\frac{6}{7}$ x - $\frac{10}{7}$ ← equation of line

5 0

4 years ago

Help me on this :( pls

Doss [256]

X = 12 dhucdjvdsiksdjfbhfud gimme brainliest

4 0

3 years ago

Read 2 more answers

Solve for x. Enter the solutions from least to greatest.

Anna [14]

Answer:

lesser x = -6

greater x = 12

Step-by-step explanation:

(x - 3)^2 - 81 = 0

(x - 3)^2 = 81

x - 3 = +/- 9

x - 3 = 9 or x - 3 = -9

x = 12 or x = -6

5 0

3 years ago

The mathematics department of a college has 7 male professors, 6 female professors, 12 male teaching assistants, and 7 female

Natalka [10]

Answer:

0.78125 or 78.125%

Step-by-step explanation:

Male professors = 7

Female professors = 6

Male T.A. = 12

Female T.A. = 7

Number of people in the department = 32

The probability that the selected person is a professor or a male is given by the probability that the person is a professor added to the probability that the person is a male, minus the probability that the person is a male professor:

$P( P\ or\ M) = P(P) +P(M) - P(P\ and\ M)\\P( P\ or\ M) =\frac{7+6}{32}+ \frac{7+12}{32}- \frac{7}{32} \\P( P\ or\ M) = 0.78125 = 78.125\%$

The probability is 0.78125 or 78.125%

6 0

3 years ago

The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de

blsea [12.9K]

Answer:

1. 15.87%

2. 6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

$P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

$\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8$

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

$P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 6) =0.0228 = 2.28\%$

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

$P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%$

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0

4 years ago