log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
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Answer: The below figure shows the graph of f(x).
Explanation: Given function, 
Since, here three conditions are given,
In first case for values x<-5 , f(x)=5, so we get a line y=5 parallel to x-axis which passes through point (0,5).
In second case, for values 
, f(x) =-2, so we get a line y=-2 parallel to x-axis which passes through point (0,-2).
In third case, for values x>6, f(x)=1, so we get a line y=1 parallel to x-axis which passes through point (0,1).
Thus, these three lines make the piecewise-defined function f(x).
It would just be -14 still
