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3 years ago

What is the radius of the circle x2+(y+6)2=25

Mathematics

1 answer:

GenaCL600 [577]3 years ago

6 0

Answer: y=7

Step-by-step explanation:

Use the vertex form to determine the values of

, and

and use these values to find the direction the parabola opens, vertex, focus, axis of symmetry, and directrix.

Direction: Opens Down

Vertex:

(

)

Focus:

(

)

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What is the length of line segment s a? 1.89 ft 2.43 ft 3 ft 7 ft

Slav-nsk [51]

The ratio of the sides will be constant. Then the value of the length of line segment SA will be 3 ft.

The missing diagram is given below.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

The triangles ΔABC and ΔSBT are the similar triangles.

Then the ratio of the sides will be constant.

BS / SA = BT / TC

10 / SA = 9 / 2.7

SA = 3

Then the value of the length of line segment SA will be 3 ft.

More about the triangle link is given below.

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2 years ago

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

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2 years ago

Which of the following is the same as 8.4×10^2

Snezhnost [94]

You need to state the answers :)

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3 years ago

What inequality matches the statement : A number is at most 40

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