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sergejj [24]
3 years ago
12

A craftsman can sell 10 jewelry sets for $500 each. He knows

Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning=\text{Price of each set}\times \text{no of set}

Earning =(500-25n)(10+n)

E=5000+500n-25n^2-250n

differentiate to get the maximum value

\frac{dE}{dn}=-50n+250

Equate \frac{dE}{dn} to get maximum value

-50n+250=0

n=\frac{250}{50}

n=5

Thus must sell 5 extra set to maximize its earnings.

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Y=1/2×-6 ×=-4 what is the solution to the system of equations
hodyreva [135]

Answer:

(-4, -8)

Step-by-step explanation:

Use the substitution method.  x = -4, so y = (1/2)x - 6 becomes:

y = (1/2)(-4) - 6, or y = -2 - 6, or y = -8.

The solution is (-4, -8).

8 0
3 years ago
Each ice cream cone at Izzy's Ice Cream Parlor contains $\frac{1}{32}$ of a gallon of ice cream. If Izzy has $\frac{3}{4}$ of a
harkovskaia [24]

Answer: 24 cones.

Step-by-step explanation:

We know that each cone contains 1/32 of a gallon of ice cream.

And Izzy has a total of 3/4 gallons.

How many cones we can make with this? This will be equal to the quotient between 3/4 gallons and 1/32 gallons, which will be equal to the number of times that we can fit 1/32 in 3/4

this is:

N = (3/4 gal)/(1/32 gal) = 24

This means that we can make 24 ice cream cones with 3/4 gal of ice cream.

5 0
3 years ago
Help please will mark brainliest!!!
solniwko [45]

Answer:

945

Step-by-step explanation:

8 0
3 years ago
The is thinking of a number which he calls n. He finds 1/3 of the number and subtracts 5
Alona [7]

Answer:

I just did it its 1/3n - 5

Step-by-step explanation:

5 0
3 years ago
I don’t understand this one
Masja [62]

Answer:

  see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

__

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

  (x +1)

Substituting x=-1 into this factor makes it be ...

  (-1 +1) = 0

__

Evaluating the first expression, we have ...

\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

5 0
4 years ago
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