Answer:
0.714 ; 0.556 ; (A1 n A2 n A3) = 0
Step-by-step explanation:
Given that :
P(oil) = 0.35
P(filter) = 0.45
P(oil n filter) = 0.25
1)
P(filter | Oil) = P(oil n filter) / P(oil)
P(filter | Oil) = 0.25 / 0.35 = 0.714
11)
P(Oil | filter) = P(oil n filter) / P(filter)
P(Oil | filter ) = 0.25 / 0.45 = 0.556
Number of red aces = 2
Queen or king = 4 + 4 = 8
Number on card greater than 3 and less than 8 = {4,5,6,7} = 4 card ; for 4 suits = 4 * 4 = 16
Total number of cards in deck = 52
Choosing without replacement :
Hence,
A1 = 2 / 52
A2 = 8 / 51
A3 = 16 / 50
(A1 n A2 n A3) ;this means card common to all three events.
However, (A1 n A2 n A3) = 0 because ;
1.) No red ace card is greater than 3 and less than 8.
11.) An ace card can neither be a king nor a queen
