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swat32
3 years ago
5

Please help dhshajgsfge

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
1/8

Explanation: There is 8 isle seats and it says what if one person would want to sit in ONE of the isle seats 1:person 8:seats
1/8
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I really need the answers to these cuz they'll make or break my grade
MrMuchimi

Answer:

whats the question? its a little blurry and hard to see

Step-by-step explanation:

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2 years ago
How is a neural network similar to a computer network? How are they different?
murzikaleks [220]
The difference in the two are that the neural network can do multiply tu hinge at the same time while the computer network is like a regular basic computer while the neural network is more advanced
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3 years ago
X/4 -3 = 1/3 + 2x solve for x
ivann1987 [24]

Answer:

Step-by-step explanation:

\frac{x}{4} - 3 = \frac{1}{3} + 2x ...... <em>(1)</em>

(1) × 12 :

3x - 36 = 4 + 24x

21x = - 40

x = - \frac{40}{21} = -1\frac{19}{21}

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2 years ago
Abdul runs 6 miles in 50 minutes. At the same rate, how many miles would he run in 35 minutes?
stepladder [879]
\frac{6miles}{50min} = \frac{x miles}{35 min}  \\ 6*35 = 50*x \\ 210 =50x \\ 210/50=50x/50 \\ x=4.2
Abdul can run 4.2 miles in 35 minutes
5 0
3 years ago
Read 2 more answers
You flip a coin and then roll a 6-sided number cube (a die).
expeople1 [14]

Answer:

a)  No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.

b) Yes.

  • Let event 1 be flipping a coin and event 2 be rolling a die.
  • Let event 1 be rolling a die and event 2 be flipping a coin.

The likelihood that any outcome will occur will not change, as the events are independent.

c) see attached

d)   12 outcomes  (H = head, T = tail, numbers represent the value of the die)

H 1           T 1

H 2          T 2

H 3          T 3

H 4          T 4

H 5          T 5

H 6          T 6

e)  

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf P(even)=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}

\implies \sf P(head)=\dfrac{1}{2}

\implies \sf P(even)\:and\:P(head)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}

6 0
2 years ago
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