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swat32
3 years ago
5

Please help dhshajgsfge

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
1/8

Explanation: There is 8 isle seats and it says what if one person would want to sit in ONE of the isle seats 1:person 8:seats
1/8
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8x-20 - 3x-1<br><br> finding c
fomenos
What’s c? Not valid question
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3 years ago
Please Help!<br><br> Find the area of the shaded region.
hodyreva [135]

Answer: 9mm

Step-by-step explanation:

5 0
2 years ago
Y = x² + 6x + 3
olganol [36]

Vertex<em> </em>is at \left(-3,-6\right)

<em>y-intercept</em> is 3.

The parabola <em>opens up</em>.

Step-by-step explanation:

The graph of the equation is hereby attached in the answer area.

Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here(x =-3), is shown with the dotted line in the graph attached.

<em>y-intercept </em>is defined as the value of y where the graph crosses the y-axis. In other words, when x=0. Putting

And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of x in the given equation y =x^{2} + 6x + 3. Here, co-efficient of

So, vertex<em> </em>is at \left(-3,-6\right)

<em>y-intercept</em> is 3.

The parabola <em>opens up</em>.

7 0
3 years ago
Describe a real-world situation that the graph could represent. Then describe the possible values for each variable
Alex777 [14]

Answer:

Speed=distance/time i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

Speed=distance/time

So, if we take distance on y axis and time on x axis with points as (distance,time)

(0,0) ==> v=0/0=0

(1,2) ==> v=1/2=0.5

(2,2) ==> v=2/2=1

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

8 0
3 years ago
Line 1 passes through the points A(-15,-8) and B(-3,0). Line 2 has
Katyanochek1 [597]

Answer:

The equation of line 3 is;

y = \frac{2}{3} x + 6

Step-by-step explanation:

Line 1 passes through the points A(-15,-8) andn B(-3,0)

Line 2 has equation shown below;

5x - 3y + 18 = 0

Line 3 is parallel to line 1 and has the same y-intercept as line 2.

We are to determine the equation of line 3.

<u>Equation of line 1:</u>

<u />

Slope = change in y-axis ÷ change in x-axis

The slope of line 1 = \frac{0 - -8}{-3 - -15}  = \frac{8}{12} = \frac{2}{3}

Picking another point (x,y) on the line;

Slope = \frac{y - 0}{x - -3}  = \frac{2}{3}

y = \frac{2}{3} x + 2 (this is the equation of line 1)

<u>Equation of line 2:</u>

<u />

We put the equation given, of line 2, in the cartesian plane format;

3y = 5x + 18

y = \frac{5}{3} x + 6

Finally, the equation of line 2 is;

y = 1\frac{2}{3} x + 6

<u>Equation of line 3:</u>

<u />

Given: Line 3 is parallel to line 1

The slopes of two parallel lines are the same so line 3 has a slope of \frac{2}{3}

Given: Line 3 has the same y-intercept as line 2

The y-intecept of line 2 is 6 (y-intercept is the value of y when x = 0)

So the equation of line 3 is;

y = \frac{2}{3} x + 6

3 0
3 years ago
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