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Marat540 [252]
3 years ago
13

A teacher asked students in his class if they had any brothers or sisters. The results are shown below. What is the chance of ra

ndomly selecting someone from this group with a brother given that they have a sister?
P(Brother|Sister)

Group of answer choices

5/12

5/17

5/9

5/14
Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

5/14

Step-by-step explanation:

Just took the test

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X – 6y - 9 = 0 x = 8y + 6 What is a resulting equation?
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Answer:

-2y + 3 = 0

Step-by-step explanation:

x - 6y - 9 = 0

-6y - 9 = -x                          subtract x from both sides

6y + 9 = x                            divide both sides by -1

x = 8y + 6

6y + 9 = 8y + 6                    replace x with 6y + 9

-2y + 9 = 6                           subtract 8y from both sides

-2y + 3 = 0                            subtract 6 from both sides

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Events X and Y are independent. The probability of X occurring is 1/3 . The probability of Y occurring is 1/2 . What is P(X and
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For independent events X,Y, \mathbb P(X\cap Y)=\mathbb P(X)\times\mathbb P(Y).

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