(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
50,000? This is my answer sorry if wrong
Step-by-step explanation:
All you have to do is multiply 55.8 by .62 to get the answer which is 34.596 but I rounded up it to 34.60
Answer:
idekqwarwera
Step-by-step explanation:
Answer:
C, 5/2
Step-by-step explanation:
3 I2x -1I + 4 = 16
Isolate absolute value:
3 I2x -1I + 4 - 4 = 16 - 4
3 I2x -1I= 12
(3 I2x -1I) / 3 = 12 / 3
I2x -1I= 4
Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x
2x -1 = 4
2x -1 + 1 = 4 +1
2x = 5
2x / 2 = 5 / 2
x = 5/2 or C
