Answer:
Probability ball: white - P(W)P(W);
Probability ball: even - P(E)P(E);
Probability ball: white and even - P(W&E).
Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).
(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient
(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).
(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.
Answer: E.
Hey,
If you meant that
than
![= \sqrt[4]{111^{5}}](https://tex.z-dn.net/?f=%3D%20%20%5Csqrt%5B4%5D%7B111%5E%7B5%7D%7D%20%20)
but you can't find the exact number.
Hope this helps :) and don't forget to choose the brainliest please :)
Yes your answer is correct... Because as per the question the equation formed should be y = 5(3)^x.
Answer:
9
Step-by-step explanation:
1, 3, 5, 9, 15, 19, 19
Answer:
Step-by-step explanation:
2>c/3
Multiply both sides of the inequality by 3.
2(3)>c/3(3)
6>c
Switch sides.
c<6
