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3 years ago

QUICK HELP ITS DUE IN 10 EEEEEEEEEEE

Mathematics

1 answer:

Svet_ta [14]3 years ago

6 0

Answer:

the answer is b

Step-by-step explanation:

pls give me brainliest plsss i gave you answer

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Which explanation best describes the answer to this problem?

Ghella [55]

754/30= 25 with a 4 left over
if everyone gets the chance to ride there will have to be 26 rides
So C is the answer

7 0

4 years ago

A box contains 2 red marbles , 3 green marbles , and 3 blue marbles

krek1111 [17]

Answer:

the box contains a total of 8 marbles .

although if you understand pixels then you would know that could stand for RGB so your color would be a very dark greenish brown

Step-by-step explanation:

no question?

5 0

4 years ago

Justin is marking a border for a garden. He walks 200 feet to the east, then turns and

ELEN [110]

Answer:

d = 233.23 feet

Step-by-step explanation:

Given that,

Justin walks 200 feet to the east, then turns and walks 120 feet due south.

We need to find the total distance walked by Justin. Let the distance be d.

We can use the Pythagoras theorem to find it such that,

$d=\sqrt{d_1^2+d_2^2} \\\\d=\sqrt{200^2+120^2} \\\\d=233.24\ feet$

So, he walk 233.23 feet in all.

3 0

3 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

The sum of two consecutive integers is 7. Find the numbers. (Enter your answers as a comma-separated list.)

DENIUS [597]

3,4?? 3+4=7 and they are right after the other ome

6 0

4 years ago