Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)? f(x) = x3 – x2 – 2x f(x) = 3x3 – 3

Question

NARA [144]

3 years ago

9

Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)? f(x) = x3 – x2 – 2x f(x) = 3x3 – 3

x2 – 6x f(x) = x3 + x2 – 2x f(x) = 3x3 + 3x2 – 6x

Mathematics

2 answers:

Rzqust [24] · Answer 1 · 2022-05-01T08:48:06+03:00

Rzqust [24]3 years ago

8 0

B) f(x) = 3x3 – 3x2 – 6x

sergeinik [125] · Answer 2 · 2022-05-01T07:25:04+03:00

sergeinik [125]3 years ago

3 0

X=1 has to give -6. Only 3x3-3x2-6x satisfies that: 3-3-6=-6; No need to anything else! Wow ... Usually there are two options left and one needs to do something else.

the other ones pass through (1,-2); (1,0) and (1,0)