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rosijanka [135]
4 years ago
14

A.) Find a general linear equation Ax+By+C=0 of the straight line that passes through the point (2,1) and is vertical.

Mathematics
1 answer:
yulyashka [42]4 years ago
5 0
<span>the straight line passes through the point (2,1) and is vertical

 x=2 (vertical), so we can have the value of B and C, x-2=0 so B=0 and C=-2
the main equation is x - 2 = 0

</span><span>inear equation Ax+By+C=0 of the straight line that passes through the point (-2,3) and is horizontal.
y=3, (horizontal)    y-3=0, so A=0, B=1 and C=-3  the main equation is y-3=0</span>
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3 years ago
Mr.Martin is giving a math test next period.The test,which is worth 100 points,has 29 problems. Each problem is worth either 5 p
blsea [12.9K]

Answer:

The second option

Step-by-step explanation:

x+y=29

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since 5x+2y=100

then 5x+2(29–x)=100

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then 3x+58=100

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Keith_Richards [23]

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3 0
4 years ago
You are graphing y &lt; 2x + 1. What type of line do you use and where do you shade?
bazaltina [42]
Since there isn't a line under the < sign, this means that we used a dotted or dashed line. The dotted or dashed line indicates that we do NOT include the boundary as part of the solution set. 

Since y is isolated and we have a less than sign, this means we shade below the dashed/dotted boundary line. Specifically, the boundary line is the graph of y = 2x+1. This boundary line goes through (0,1) and (1,3). Again, points on this boundary line are NOT part of the solution set. 

So in summary we have:
A dashed or dotted boundary line
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Answer:

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