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ratelena [41]
3 years ago
6

Maya runs 10 miles and 85 minutes at the same rate how many minutes would she take to run 8 Miles ​

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer: 68

Step-by-step explanation:

10 = 8

85=x

than you cross multiple and divide

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A scuba diver is swimming in the ocean 10 feet below sea level. Then, she dives down 12
Elis [28]

Answer:

22 ft

Step-by-step explanation:

Simply add 12 to 10 and you'll get the relative position.

5 0
3 years ago
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Which mixed number is equivalent to the improper function below? 46/10
Valentin [98]

Answer:

B. 4 and 6/10

Step-by-step explanation:

in order to find this answer i've always had a trick where i first off find an even number to divide these with and in this case that would be 4 and then the leftovers would be 6/10 and in this case your answer would be right there 4 and 6/10 but if needed to be simplified it would be 4 and 3/5

hope this helps, if it did please make sure to like and rate and give me the brainliest if possible!

have a good day!

6 0
3 years ago
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A waitress works 1.75 hours less in the afternoon than in the evening. If she works 5      1/8
gayaneshka [121]
Let x be the number of hours that the waitress works in the evening.

We know for our problem that she works 5 \frac{1}{8} in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>x=5 \frac{1}{8} -1.75
<span>Since </span>\frac{1}{8} =0.125, we can rewrite our expression:
x=5.125-1.75
x=3.375

We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction: 3 \frac{3}{8} hours.
3 0
3 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
2 years ago
Help plz : 4x-2(x-3)=10+(-9)
Dominik [7]
Distribute -2(x - 3)

4x - 2x + 6 = 10 + -9

Simplify

2x = -5

x = -2.5
7 0
3 years ago
Read 2 more answers
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