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3 years ago

Which is the angle measure represented by 3 rotations clockwise?

Mathematics

2 answers:

kenny6666 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

by rotating it clockwise 3 time you will multiply 3x360 because their is 360 degree in a complete circle

aleksandr82 [10.1K]3 years ago

4 0

Answer:

-1080

Step-by-step explanation:

360 x 3 = 1080

But rotating clockwise give you a negative angle measurement so it’s -1080

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Factoring by grouping 12x^2+11x+2=0

Alex_Xolod [135]

Step-by-step explanation:

(12)(2) = 24 Find 2 numbers whose product is 24 and whose sum is 11 (8 and 3 work)

Rewrite 11x as 8x+3x and factor by grouping:

12x2 + 8x + 3x + 2 = 0

4x(3x+2) + 1(3x+2) = 0

(3x+2)(4x+1) = 0

x = -2/3 or x = -1/4

7 0

4 years ago

.The area of a square is 900 square inches. What is the perimeter?

Irina-Kira [14]

Answer:

area=s²

$\sqrt{900$ =30

side=30

perimeter=side*4

30*4=120

<h2>D.120inches</h2>

Step-by-step explanation:

8 0

3 years ago

Help me please ignore the other stuff im too lazy to crop it

son4ous [18]

-3,5.
hope that helps

5 0

3 years ago

Please help with the questions in the image

iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

Question a

We have $-2x^3 + 5x^2 + 9$

m = slope = derivative

Find the derivative / slope of $-2x^3 + 5x^2 + 9$

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

$\frac{d}{dx}(-2x^3 + 5x^2 + 9)$

$-6x^2 + 10x$

$m = -6x^2 + 10x$ when x = a

Now that we have this information, we can answer question b

Question b

The tangent line for Point (1, 12)

First find the slope by using our derivative.

$m = -6x^2 + 10x$

$m = -6(1)^2 + 10(1)$

$m = -6 + 10x$

$m = 4$

Now that we have our slope, use point slope form to find our tangent line

$y - 12 = 4(x - 1)$

$y(x) = 4x + 8$

Now lets do the same for the Point (2, 13)

Find the slope at the point.

$m = -6x^2 + 10x$

$m = -6(2)^2 + 10(2)$

$m = -24 + 10$

$m = -4$

Now find the tangent line using point slope form of a line.

$y(x) - 13 = -4(x - 2)$

$y(x) = -4x + 21$

Now graph the lines, which I have done and you can see by viewing the image I have attached.

6 0

4 years ago

What are the values of the coefficients and constant term of 0 = 4 – 7x2 + x in standard form?

katen-ka-za [31]

ANSWER

$a = - 7$

$b = 1$

$c = 4$

EXPLANATION

The given quadratic equation is:

$0 = 4 - 7 {x}^{2} + x$

We rewrite in the standard quadratic equation form to obtain,

$- 7 {x}^{2} + x + 4 = 0$

Comparing this to the general standard quadratic equation.

$a {x}^{2} + bx + c = 0$

We have my

$a = - 7$

$b = 1$

$c = 4$

8 0

3 years ago

Read 2 more answers