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Karolina [17]
3 years ago
14

Which ordered pair is a solution of the equation?

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

  A  Only (2, 3)

Step-by-step explanation:

The given equation is in point-slope form:

  y -k = m(x -h) . . . . . a line with slope m through point (h, k)

The point in the given equation is ...

  (h, k) = (2, 3)

so you know the equation is satisfied at that point.

__

When you try the other point, you find ...

  For (x, y) = (3, 2), you have

  2 -3 = 5(3 -2)

  -1 = 5(1) . . . . FALSE

Point (3, 2) does not satisfy the equation.

  Only (2, 3) is a solution of the equation

_____

Of course, the equation of a line is satisfied by an infinite number of points. Of the two listed here, only (2, 3) is a solution.

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Answer:

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Step-by-step explanation:

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11111nata11111 [884]

Answers:

  1. The equation is W = 33T + 500
  2. After 14 minutes, there are <u>   962   </u> liters of water.

=======================================================

Explanation:

  • T = number of minutes
  • 33T = amount of added water in liters, since we're adding 33 liters per min.
  • 33T+500 = adding on the initial 500 liters

This leads to the equation W = 33T + 500

------------------------

Plug in T = 14

W = 33T + 500

W = 33*14 + 500

W = 462 + 500

W = 962 liters of water are in the pond after 14 minutes

7 0
2 years ago
Write the equation in the slope-intercept form. 2x − 3y 6
SSSSS [86.1K]
Do you mean
2x( +  \: or - )3y = 6
8 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
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