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3 years ago

If f(x + 2) = 6x2 + 5x − 8. Find f(6).

Mathematics

1 answer:

Blababa [14]3 years ago

6 0

Answer:

108

Step-by-step explanation:

We can rewrite f(x+2) to make it easier to evaluate:

f(x+2) = (6x +5)x -8

Since we want f(6), we want x+2 = 6, or x=4.

f(6) = (6·4 +5)·4 -8 = 29·4 -8

f(6) = 108

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In the left column: how was the numerical part of the answer found (addition, subtraction )

Setler79 [48]

You can find the numerical part of the answer because it is the same on the right side.

For example:
¹ <<==== Regrouped
89
+
67
---------
146 <<=== I had to press space so I could position it.

So that also happens in subtraction, the left side can be found by doing the same steps in the right column.
For example:

67
- <<=== this time there was no regrouping
12
-------
55

5 0

3 years ago

What is the value of n in the equation shown below? 2² x 2 = (24)

ANEK [815]

The answer I get

8=24
No solution

3 0

3 years ago

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into n equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as n approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

2 years ago

5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0

2 years ago

<333

Gnom [1K]

(210+200+190+180+300+150+90+x)/8=200
(1320+x)/8=200 /*8
1320 +x=1600
X=1600-1320
X= 280

6 0

3 years ago