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3 years ago

Match The Following, 26 POINTS HELP FAST

Mathematics

2 answers:

zavuch27 [327]3 years ago

6 0

The formula for the volume of a cone is:

$1/3\pi r^{2} h$

The formula for the volume of a cylinder is:

$\pi r^2h$

The formula for the volume of a triangular prism is:

$bh$

The formula for the volume of a pyramid is:

$1/3bh$

The formula for the volume of a rectangular prism is:

$lwh$

liberstina [14]3 years ago

3 0

Answer:

$1)lwh = rectangular \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: prism \\ 2)bh = traingular \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: prism \\ 3) \frac{1}{3} bh = pyramid \\ 4)\pi {r}^{2} h = cylinder \\ 5) \frac{1}{3} \pi {r}^{2} h = cone$

hope this helps you.

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How do you reduce 15/16

alina1380 [7]

Answer:

you can't because they don't have common factors

Step-by-step explanation:

8 0

3 years ago

Assume that all triangles have interior angles less than 90°.A surveyor sights on a survey marker that is 132.3m distant. She ne

Vadim26 [7]

Answer:

85.9 m

Step-by-step explanation:

The law of sines can help figure this.

The remaining angle in the triangle is ...

180° -75° -68° = 37°

This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...

b/sin(B) = c/sin(C)

b = sin(B)·c/sin(C) = 132.3·sin(37°)/sin(68°) ≈ 85.873 . . . meters

The surveyor is about 85.9 meters from the second marker.

4 0

3 years ago

PLS 40 points

Pavlova-9 [17]

Step-by-step explanation:

Let $p1$ be the point $(-1,4)$

Let $p2$ be the point $(3,-4)$

The equation of the line passing through two points $p1=(x_{1},y_{1})$

and $p2=(x_{2},y_{2})$ is $\frac{y-y_{1}}{x-x_{1}} =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

substituting $p1,p2$ in the above equation yields

$\frac{y-4}{x-(-1)}=\frac{-4-4}{3-(-1)}$

which when simplified gives $\frac{y-4}{x+1}=\frac{-8}{4}$

which when further simplified gives $2x+y=2$

5 0

3 years ago

The largest major arc is:<br> MHJ<br> JMG<br> GNM<br> HLI

crimeas [40]

Answer:

the correct answer is HLI

7 0

2 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago