Write the equation of a line that passes through the points (-2, 3) and (-4, 4) in slope intercept form (y=mx+b).
1 answer:
Step-by-step explanation:
first step is to find the gradient of the line which "m" on the equation
gradient formula is y2 - y1 ÷ x2 - x1 = -½ as shown on the picture we substituted those points given
2nd step is to substitute on the equation y=mx+c
m= -½
y= 3 (you can choose any from those given points but in my case I chose point A)
x= -2
c= ? only unknown variable so we can can calculate it
substitute as shown on the picture to get c= 2
therefore our equation of the line will be y= -½x+2
You might be interested in
By inspection, it's clear that the sequence must converge to 
because
when
is arbitrarily large.
Now, for the limit as
to be equal to is to say that for any 
, there exists some 
such that whenever 
, it follows that
From this inequality, we get
As we're considering, we can omit the first inequality.
We can then see that choosing
will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that 
.
when
Now, for the limit as
From this inequality, we get
As we're considering
We can then see that choosing