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2 years ago

Eight dollars more than one-third the price of a medium pizza is $13. What is the price of the pizza?

Mathematics

2 answers:

Bezzdna [24]2 years ago

7 0

(13-8) / (1/3)

$5 for 1/3 of the pizza, that means that the entire pizza is $15.

xeze [42]2 years ago

3 0

$17.75 is the cost of the pizza

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Find the value of c that would make the following expression a

Sunny_sXe [5.5K]

Answer:

c = 196

Step-by-step explanation:

To obtain a perfect square trinomial

Add ( half the coefficient of the x- term )² to x² + 28x

x² + 2(14)x + (14)², that is

x² + 28x + 196

= (x + 14)² ← a perfect square

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2 years ago

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posledela

Answer:

Step-by-step explanation:

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2 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

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3 years ago

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Eddi Din [679]

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Step-by-step explanation:

h(x)=12/x

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2 years ago

Amanda has 4 liters of juice and some glasses. She will pour 1/4 liter of juice into each glass. What is the total number of gla

scZoUnD [109]

Answer:

16 glasses

Step-by-step explanation:

If 1 glass = 1/4 liter of juice

then 16 glasses = 4 liters of juice

because 4 divided by 1/4 = 16

8 0

3 years ago