1 modulo 9 is the set of numbers as follows:
(0(9) + 1), (1(9) + 1, ....)
which is:
1, 10, 19
All we have to do is divide 1000 by 9, and round down.
1000/9 = 111.111......
There are 111 numbers.
Now let us check our work.
the set is as follows:
(1,10,19, ....... (111)9 +1)
(1, 10, 19 ........ 1000)
We are within 1000.
Therefore, 111 of the 1000 smallest positive integers are congruent to 1 modulo 9.
Answer:
25/10
Step-by-step explanation:
Make the fractions improper by multiplying the whole number by the denominator and then adding the numerator (if this makes sense).
This makes 5x10=50+3=53/10
Do the same for the second fraction. 2x5=10+4=14/5
Then make the denominators the same, and in this case all you need to do is multiply both sides of 14/5 by 2, so that makes 28/10.
Now, just take it away.
53/10-28/10=25/10, which can be then simplified into 2 1/2 or 5/2.
<em>503 / 100</em>
<em>Convert the mixed number 5
3
100 into an improper fraction first by multiplying the denominator (
100
) by the whole number part (
5
) and add the numerator (
3
) to get the new numerator. Place the new numerator (
503
) over the old denominator (
100
)
. 503
/100
.</em>
Thanks,
<em>Deku ❤</em>
Answer:
360 m/hr
Step-by-step explanation:
speed = distance/time
So, the slower butterfly can fly
(1866-66)m/5hr = 360 m/hr
<h2>Given :</h2>
<h2>Solution : </h2>
Through the statement above we have,
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