Question

During the 2019 regular season, the Washington Nationals professional baseball team won 93 games and lost 69 games. What percentage of its games did the team win?

Answer 1

The percentage of its games that the team won is 57.4%

Step-by-step explanation:

The percentage of an Event = (Number of favorable outcomes / Total

number of possible outcomes) × 100%

During the 2019 regular season, the Washington Nationals professional

baseball team won 93 games and lost 69 games

We need to find the percentage of its games that the team won

1. Find the total number of games

2. To find the percentage of win, divide the number of the won games

    by the total number of games and multiply the quotient by 100%

3. To find the percentage of lose, divide the number of the lost games

    by the total number of games and multiply the quotient by 100%

∵ The team won 93 games

∵ The team lost 69 games

∴ The total number of games = 93 + 69 = 162 games

∵ P(won) = [n(won)/n(all)] × 100%

∵ n(won) = 93

∵ n(all) = 162

∴ P(won) = $\frac{93}{162}$ × 100%

∴ P(won) = 57.4%

The percentage of its games that the team won is 57.4%

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