I need help fast!!!

Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the

victus00 [196]

Answer:

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B) = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B') = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Step-by-step explanation:

The joint probability distribution for the number of bottles of liquor and the number of cartons of cigarettes imported by Canadians who have visited the United States for 2 or more days is given in the question as

V | B

C | 0 | 1

0 | 0.62 | 0.16

1 | 0.07 | 0.15

Note that B = bottle liquor

C = Carton cigarettes

V is each variable

Let the probability of bringing a bottle of liquor into the country be P(B), that is, the probability of bringing 1 bottle liquor into the country.

The probability of not bringing a bottle of liquor into the country is P(B'), that is, the probability of bringing 0 bottle liquor into the country.

Let the probability of bringing a carton of cigarettes into the country be P(C), that is, the probability of bringing 1 carton cigarettes into the country.

The probability of not bringing a carton of cigarettes into the country is P(C'), that is, the probability of bringing 0 carton cigarettes into the country.

From the joint probability table, we can tell that

P(B n C) = 0.15

P(B n C') = 0.16

P(B' n C) = 0.07

P(B' n C') = 0.62

Find the marginal probability distribution of the number of bottles imported.

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B)

P(B) = P(B n C) + P(B n C') = 0.15 + 0.16 = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B')

P(B') = P(B' n C) + P(B' n C') = 0.07 + 0.62 = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Hope this Helps!!!

8 0

3 years ago

What does Pi =<br><br><br> Vxbbbbnnnnnnnnnnnbvvvcccccccccvggvvvvffffff

777dan777 [17]

Answer: 3.14

Step-by-step explanation : 3.14159265359

8 0

3 years ago

Read 2 more answers

The sum of the numerator and the denominator of the certain fraction is equal to 4,140. When the fraction was reduced, the resul

morpeh [17]

Answer:

1449/2691

Step-by-step explanation:

1449+2691= 4140

8 0

4 years ago

Which expression is equivalent to (x^27y)^1/3?

Kazeer [188]

Answer:

It's the second one

Step-by-step explanation:

If you use exponent rules (a*b)^n=a^n*b^n. Raise each term separately to 1/3 (by multiplying by 1/3) and then you get x^9 (y^1/3)

8 0

3 years ago

Nico is saving money for his college education. He invests some money at 6%, and $1600 less than that amount at 4%. The invest

strojnjashka [21]

Let's say the amounts are "a" and "b"
6% 4%

now... we dunno what "a" is, but nevermind, whatever that is, "b" invested at 4%, is 1600 less than that or less than "a", namely b = a - 1600

so.. "a" is the bigger amount than "b" by 1600, but no matter

what is 6% of a? well, 6/100 * a or 0.06a, that's how much it yielded
what is 4% of b? well, 4/100 * b, or 0.04b, that's much it earned in interests

we know, their yield, or total in earned interest is 156, so.. whatever those yields are, they add up to 156 or

0.06a + 0.04b = 156

now $\bf \begin{cases}
\boxed{b}=a-1600\\\\
0.06a+0.04b=156\\
----------\\
0.06a+0.04\left( \boxed{a-1600} \right)=156
\end{cases}$

solve for "a", to see how much was invested at 6%

how much is "b"? well, b = a - 1600

7 0

3 years ago