Amy bought 5lbs., 11oz. Of turkey cold cuts and 6lb., 12 oz. Of ham cold cuts. How much did she buy total? You should convert an
2 answers:
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Answer:
1, i) equation for Mike's Repair Shop = $65x + $100
ii) Amy's Auto Repair = $80x + $40
2. 65x + 100 = 80x + 40
3. x = 4
4. Therefore the number of hours at which the cost both auto repair shops are the same is x = 4 hours.
5. If it takes only three hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $803 + $40 = $280 and Mike's will cost = $65
3 + $100 = $295.
6. If it takes only six hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $806 + $40 = $520 and Mike's will cost = $65
6 + $100 = $490.
7. Amy's Auto repair service is advertising to encourage customers with quick repairs to use their service because their cost is less for quick repairs but more for lengthy repairs.
Step-by-step explanation:
i) x = number of hours worked
ii) y = total cost
1, i) equation for Mike's Repair Shop = $65x + $100
ii) Amy's Auto Repair = $80x + $40
2. 65x + 100 = 80x + 40
3. 15x = 60, therefore x = 4
4. Therefore the number of hours at which the cost both auto repair shops are the same is x = 4 hours.
5. If it takes only three hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $803 + $40 = $280 and Mike's will cost = $65
3 + $100 = $295.
6. If it takes only six hours to fix the car the Amy' repair shop will be the cheapest because Amy's auto repair will cost = $806 + $40 = $520 and Mike's will cost = $65
6 + $100 = $490.
7. Amy's Auto repair service is advertising to encourage customers with quick repairs to use their service because their cost is less for quick repairs but more for lengthy repairs.
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = ≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = ≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ